Garden Highpro Filter ProActiv - 160/840 m3/h

Code: PA840
8 ratings
–19 %
Garden Highpro Filter ProActiv - 160/840 m3/h
–19 % €133,71
SKLADEM (17 pcs)
Delivery to:
17.07.2024
Delivery offer
Popular carbon filter against with activated carbon from coconut. It helps to deal with odors inside growing and other areas.

Detailed information

Dárky k objednávce zdarma
Dárky k objednávce zdarma
Do poznámky k objednávce se zmiňte o dárku zdarma a rádi Vám něco připravíme :-)
Oficiální česká distribuce
Oficiální česká distribuce
Klademe důraz na kvalitní produkty a skladování. Naše zboží pochazí pouze z oficiální distribuce. Za kvalitu skladování ručíme !
Ověřený obchod
Ověřený obchod
Jsme důvěryhodný a ověřený obchod na základě recenzí od reálných zákazníků.
Zboží skladem
Zboží skladem
Většinu sortimentu držíme skladem a je připraven k okamžité expedici.

Product detailed description

Filter Pro Activ 160/840 m3/hs with activated carbon against odor. Diameter 160 mm, air flow 840 m3/h, length 55 cm. Large odor filter. The particles of activated carbon from coconut are very small (0.4 to 0.8 mm) and therefore the surface that neutralizes the smell is more compact and larger - 730 g/m2. Multi-layered fleece mats airtightly prevent any intake/escape of unfiltered air, reduce atmospheric pressure and effectively increase air flow.

For the correct functioning of the Pro Activ 1160/460 m3/h odor filter, it is it is necessary to keep the ambient humidity up to a maximum of 65%. Compared to conventional odor filters, it is smaller, more efficient, safer and, if used correctly, more durable. A practical gadget are the built-in fixed eyes for hanging the filter using Lighthanger or Prohanger hangers.

Calculation to choose a suitable filter
We calculate the volume of air in the room, where we multiply the length of the room (m) by the width of the room (m) and the height of the ceiling (m).
For example: A room with a length of 4 m, a width of 3 m and a ceiling height of 2 m => 4 x 3 x 2 = 24 m3
We multiply the resulting volume of air by the number 60 (i.e. the number of minutes per hour), thereby finding out how much air needs to be purified in 1 hour.
We will compare the result with the maximum performance of the selected filter. If its max. output is higher than our result, the filter is sufficient for the space.

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